87=x^2+7

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Solution for 87=x^2+7 equation:



87=x^2+7
We move all terms to the left:
87-(x^2+7)=0
We get rid of parentheses
-x^2-7+87=0
We add all the numbers together, and all the variables
-1x^2+80=0
a = -1; b = 0; c = +80;
Δ = b2-4ac
Δ = 02-4·(-1)·80
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*-1}=\frac{0-8\sqrt{5}}{-2} =-\frac{8\sqrt{5}}{-2} =-\frac{4\sqrt{5}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*-1}=\frac{0+8\sqrt{5}}{-2} =\frac{8\sqrt{5}}{-2} =\frac{4\sqrt{5}}{-1} $

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